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pure math 10 question

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jordanpischke View Drop Down
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    Posted: 18 December 2007 at 8:04pm

I did part of this question, but once I get to a certain point I dont know what to do. This is a subtraction with fractions.

Subtract:        &nb sp;         &nb sp;        

                         2                                                         3

             ------------------               -          ----------------------

               (x2 –3x-10)                                          (x2 –5x-14)

Now I can factor the bottoms of both fractions to get

 

                            2                                                      3

             ------------------             -               ---------------------

               (x+2) (x-5)                                             (x+2) (x-7)

 

Right here is where I get stuck. I know that I have to find a common denominator to subtract these, but the fact that they are x's in the fractions confuse me.  Normally I wouldn't have a problem, but I havent done one of these before. That fact that they are in brackets is what screws me up. If I multiply them by something to make them equal they wont end up equal, because the x's will be different.  I need some help.

 

 

 

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hoginds24 View Drop Down
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Post Options Post Options   Thanks (0) Thanks(0)   Quote hoginds24 Quote  Post ReplyReply Direct Link To This Post Posted: 18 December 2007 at 8:11pm
multiply the opposite by the bottom of the other?
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Post Options Post Options   Thanks (0) Thanks(0)   Quote Pezzer Quote  Post ReplyReply Direct Link To This Post Posted: 18 December 2007 at 8:15pm
It has been forever since I've done this and I can't say I remember exactly how.  Through a little algebra I simplified it to (x^2 - 5x - 14) * (2x^2 - 6x - 20) - 3.  Don't ask me how but it should still give you the same number as the original function.
Suck, sqeeze, bang, blow, and GO!

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jordanpischke View Drop Down
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Post Options Post Options   Thanks (0) Thanks(0)   Quote jordanpischke Quote  Post ReplyReply Direct Link To This Post Posted: 18 December 2007 at 8:20pm

Ok so the common denominator is  (x+2) (x-5) (x-7). the tops would be 2(x-7) - 3(x-5). you multiply the coefficents into the fractions 2x-14-3x+15  and simplify to get -x+1 over (x+2)(x-5)(x-7). Yay I figured it out.

The reason it confused me was that I thought what I did to one fraction I would have to do to the other, but their is no equals sign and when you find a common denominator you have to multiply each fraction by something different.



Edited by jordanpischke - 18 December 2007 at 8:21pm
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Post Options Post Options   Thanks (0) Thanks(0)   Quote jjclown23 Quote  Post ReplyReply Direct Link To This Post Posted: 18 December 2007 at 9:00pm
Cha Ching:



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Edited by jjclown23 - 18 December 2007 at 9:01pm
A-5
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